(6x^2-12)/3x-4=2x

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Solution for (6x^2-12)/3x-4=2x equation:


x in (-oo:+oo)

x*((6*x^2-12)/3)-4 = 2*x // - 2*x

x*((6*x^2-12)/3)-(2*x)-4 = 0

x*((6*x^2-12)/3)-2*x-4 = 0

(x*(6*x^2-12))/3-2*x-4 = 0

(x*(6*x^2-12))/3+(-2*3*x)/3+(-4*3)/3 = 0

x*(6*x^2-12)-2*3*x-4*3 = 0

6*x^3-18*x-12 = 0

6*x^3-18*x-12 = 0

6*(x^3-3*x-2) = 0

x^3-3*x-2 = 0

{ 1, -1, 2, -2 }

1

x = 1

x^3-3*x-2 = -4

1

-1

x = -1

x^3-3*x-2 = 0

-1

x+1

x^2-x-2

x^3-3*x-2

x+1

-x^3-x^2

-x^2-3*x-2

x^2+x

-2*x-2

2*x+2

0

x^2-x-2 = 0

DELTA = (-1)^2-(-2*1*4)

DELTA = 9

DELTA > 0

x = (9^(1/2)+1)/(1*2) or x = (1-9^(1/2))/(1*2)

x = 2 or x = -1

x in { -1, 2, -1}

6*(x+1)^2*(x-2) = 0

(6*(x+1)^2*(x-2))/3 = 0

(6*(x+1)^2*(x-2))/3 = 0 // * 3

6*(x+1)^2*(x-2) = 0

( 6 )

6 = 0

x belongs to the empty set

( x+1 )

x+1 = 0 // - 1

x = -1

( x-2 )

x-2 = 0 // + 2

x = 2

x in { -1, -1, 2 }

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